Electric field issues related to capacitors

How does a spherical capacitor affect electric field strength?

Since V is directly proportional to electric field so as V' decreases (1\2) (1+K) times the electric field strength also decreases by the same amount. This is the required answer. A spherical capacitor has charges + Q and - Q on its inner and outer conductors. Find the electric potential energy stored in the capacitor?

What happens when a capacitor is faced with a decreasing voltage?

When a capacitor is faced with a decreasing voltage, it acts as a source: supplying current as it releases stored energy (current going out the positive side and in the negative side, like a battery). The ability of a capacitor to store energy in the form of an electric field (and consequently to oppose changes in voltage) is called capacitance.

What happens if a capacitor is a positive or negative conductor?

As the electric field is established by the applied voltage, extra free electrons are forced to collect on the negative conductor, while free electrons are “robbed” from the positive conductor. This differential charge equates to a storage of energy in the capacitor, representing the potential charge of the electrons between the two plates.

How to find the capacitance of a capacitor with continuously varying dielectric?

For finding the capacitance of the capacitor having continuously varying dielectric, we would have to perform integration over whole variation. The Potential Difference between AB is 6 V. Considering the branch AB, the capacitors 2 μ F and 5 μ F are in parallel and their equivalent capacitance = 2 + 5 = 7 μ F.

What happens if a capacitor is connected to a battery?

An air filled, parallel plate capacitor with capacitance C is connected to a battery with voltage V resulting in a stored charge Q. The battery remains connected and the separation between the plates is increased from d to 2d. Determine the new values of the following quantities in terms of their original values…

What happens if two capacitors are connected in a series combination?

Since both the capacitors are connected in series combination so charge on both the capacitors would be same which lead to same potential difference V across each capacitor which is Q = CV = Cξ/2 in the absence of dielectric. Now one of the capacitor is being filled up with dielectric of dielectric constant K.